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midpoint (0, 1/7),(-6/7 ,0)range of (4x^2+4x+1)/xdomain of 7/(\frac{x){x+7}}inverse of f(x)=(x+8)^3+7parallel y= 1/2 x-6
Frequently Asked Questions (FAQ)
What is the symmetry 8-x^2 ?
The symmetry 8-x^2 is x=0