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Popular Functions >

extreme f(x)=(2x-8)^{2/3}

Solution

extreme points

f (x) = (2 x - 8)^{\frac{2}{3}}

Solution

Minimum (4, 0)

Solution steps

f^{'} (x) = \frac{4}{3 ( 2 x - 8 ) ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

(2 x - 8)^{\frac{2}{3}} : 0

Minimum (4, 0)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=(2x-8)^{2/3} ?
The extreme f(x)=(2x-8)^{2/3} is Minimum(4,0)