What is the extreme f(x)=-0.2t^2+1.6t+98.7 ?

The extreme f(x)=-0.2t^2+1.6t+98.7 is Maximum(4,101.9)

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extreme f(x)=-0.2t^2+1.6t+98.7

extreme points

f (x) = - 0.2 t^{2} + 1.6 t + 98.7

Maximum (4, 101.9)

Solution steps

f^{'} (t) = - 0.4 t + 1.6

Find intervals:

Increasing

: - \infty < t < 4,

Decreasing

: 4 < t < \infty

Plug

t = 4

into

- 0.2 t^{2} + 1.6 t + 98.7 : 101.9

Maximum (4, 101.9)

What is the extreme f(x)=-0.2t^2+1.6t+98.7 ?
The extreme f(x)=-0.2t^2+1.6t+98.7 is Maximum(4,101.9)