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midpoint
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inflection 1/(2sqrt(x))range of f(x)=-x^2+6x-1extreme f(x)=(x^2+x+2)/(x-1)inverse of f(x)=-x^2-4x-3distance (0,0),(2,-3)
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-4),(3,-2) ?
The midpoint (-2,-4),(3,-2) is (1/2 ,-3)