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Popular Functions >

range of y=-x^2+1

Solution

range

y = - x^{2} + 1

Solution

f (x) \leq 1

+1

Interval Notation

(- \infty, 1]

Solution steps

Vertex of

- x^{2} + 1 :

Maximum

(0, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 1)

f (x) \leq 1

Graph

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Frequently Asked Questions (FAQ)

What is the range of y=-x^2+1 ?
The range of y=-x^2+1 is f(x)<= 1