What is the inverse of f(x)=100(1-t/(40))^2 ?

The inverse of f(x)=100(1-t/(40))^2 is -4sqrt(t)+40,4sqrt(t)+40

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inverse of f(x)=100(1-t/(40))^2

inverse

f (x) = 100 (1 - \frac{t}{40})^{2}

- 4 t + 40, 4 t + 40

Solution steps

x = 100 (1 - \frac{t}{40})^{2}

Replace

t

with

x

t = 100 (1 - \frac{x}{40})^{2}

Solve for

x, t = 100 (1 - \frac{x}{40})^{2}

- 4 t + 40, 4 t + 40

What is the inverse of f(x)=100(1-t/(40))^2 ?
The inverse of f(x)=100(1-t/(40))^2 is -4sqrt(t)+40,4sqrt(t)+40