What is the domain of f(x)= 1/(sqrt(x-9)) ?

The domain of f(x)= 1/(sqrt(x-9)) is x>9

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domain of f(x)= 1/(sqrt(x-9))

domain

f (x) = \frac{1}{x - 9}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

What is the domain of f(x)= 1/(sqrt(x-9)) ?
The domain of f(x)= 1/(sqrt(x-9)) is x>9