What is the asymptotes of f(x)= 1/(16-x^2) ?

The asymptotes of f(x)= 1/(16-x^2) is Vertical: x=-4,x=4,Horizontal: y=0

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asymptotes of f(x)= 1/(16-x^2)

asymptotes

f (x) = \frac{1}{16 - x ^{2}}

Vertical : x = - 4, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{16 - x ^{2}} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{1}{16 - x ^{2}} : y = 0

Slant Asymptotes of

\frac{1}{16 - x ^{2}} :

None

Vertical : x = - 4, x = 4, Horizontal : y = 0

What is the asymptotes of f(x)= 1/(16-x^2) ?
The asymptotes of f(x)= 1/(16-x^2) is Vertical: x=-4,x=4,Horizontal: y=0