What is the inverse of f(x)=2x^2-5x+1 ?

The inverse of f(x)=2x^2-5x+1 is (5+sqrt(8x+17))/4 ,(5-sqrt(8x+17))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=2x^2-5x+1

inverse

f (x) = 2 x^{2} - 5 x + 1

\frac{5 + 8 x + 17}{4}, \frac{5 - 8 x + 17}{4}

Solution steps

y = 2 x^{2} - 5 x + 1

Replace

x

with

y

x = 2 y^{2} - 5 y + 1

Solve for

y, x = 2 y^{2} - 5 y + 1

\frac{5 + 8 x + 17}{4}, \frac{5 - 8 x + 17}{4}

What is the inverse of f(x)=2x^2-5x+1 ?
The inverse of f(x)=2x^2-5x+1 is (5+sqrt(8x+17))/4 ,(5-sqrt(8x+17))/4