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midpoint
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symmetry x^2+y-9=0inverse of f(x)=8-7e^xdomain of 5/x+7/(x+7)domain of f(x)=(x^2+2x+1)/(x-3)simplify (-2.4)(13.1)
Frequently Asked Questions (FAQ)
What is the midpoint (0,-8),(-7,-4) ?
The midpoint (0,-8),(-7,-4) is (-7/2 ,-6)