What is the domain of f(x)= 5/(t^2-1) ?

The domain of f(x)= 5/(t^2-1) is t 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)= 5/(t^2-1)

domain

f (x) = \frac{5}{t ^{2} - 1}

t < - 1 or - 1 < t < 1 or t > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

t = 1, t = - 1

The function domain

t < - 1 or - 1 < t < 1 or t > 1

What is the domain of f(x)= 5/(t^2-1) ?
The domain of f(x)= 5/(t^2-1) is t<-1\lor-1<t<1\lor t>1