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Popular Functions >

inverse of 1/(4^x+1)

Solution

inverse

\frac{1}{4 ^{x} + 1}

Solution

\frac{ln ( \frac{1}{x} - 1 )}{2 ln ( 2 )}

Solution steps

y = \frac{1}{4 ^{x} + 1}

Replace

x

with

y

x = \frac{1}{4 ^{y} + 1}

Solve for

y, x = \frac{1}{4 ^{y} + 1}

\frac{ln ( \frac{1}{x} - 1 )}{2 ln ( 2 )}

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of 1/(4^x+1) ?
The inverse of 1/(4^x+1) is (ln(1/x-1))/(2ln(2))