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midpoint
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range of 3x^2+6xrange of f(x)=sqrt(x)+6perpendicular 6x+3y=-6domain of f(x)=(1+4x)/(2x-1)critical 12x^2-204x+594
Frequently Asked Questions (FAQ)
What is the midpoint (3,-5),(9,5) ?
The midpoint (3,-5),(9,5) is (6,0)