What is the inverse of f(x)=sqrt(1/(x^2)-1) ?

The inverse of f(x)=sqrt(1/(x^2)-1) is sqrt(1/(x^2+1)),-sqrt(1/(x^2+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=sqrt(1/(x^2)-1)

inverse

f (x) = \frac{1}{x ^{2}} - 1

\frac{1}{x ^{2} + 1}, - \frac{1}{x ^{2} + 1}

Solution steps

y = \frac{1}{x ^{2}} - 1

Replace

x

with

y

x = \frac{1}{y ^{2}} - 1

Solve for

y, x = \frac{1}{y ^{2}} - 1

\frac{1}{x ^{2} + 1}, - \frac{1}{x ^{2} + 1}

What is the inverse of f(x)=sqrt(1/(x^2)-1) ?
The inverse of f(x)=sqrt(1/(x^2)-1) is sqrt(1/(x^2+1)),-sqrt(1/(x^2+1))