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midpoint
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domain of f(x)=sqrt(x^2+5)inverse of log_{1/2}(x^5)distance (-3,9),(-5,2)range of f(x)=(3x)/(7x-6)domain of f(x)=-2(x-4)^2+8
Frequently Asked Questions (FAQ)
What is the midpoint (-3,-5),(1,1) ?
The midpoint (-3,-5),(1,1) is (-1,-2)