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midpoint
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inverse of x^2+3x+2domain of f(x)=-xmidpoint (-5,-3),(3,5)domain of f(x)=(5x)/(x^2-3x-4)extreme 1/(x^2)
Frequently Asked Questions (FAQ)
What is the midpoint (2,-1),(2,5) ?
The midpoint (2,-1),(2,5) is (2,2)