What is the inverse of f(x)=4(x+1)^2-1 ?

The inverse of f(x)=4(x+1)^2-1 is (sqrt(x+1))/2-1,-(sqrt(x+1))/2-1

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inverse of f(x)=4(x+1)^2-1

inverse

f (x) = 4 (x + 1)^{2} - 1

\frac{x + 1}{2} - 1, - \frac{x + 1}{2} - 1

Solution steps

y = 4 (x + 1)^{2} - 1

Replace

x

with

y

x = 4 (y + 1)^{2} - 1

Solve for

y, x = 4 (y + 1)^{2} - 1

\frac{x + 1}{2} - 1, - \frac{x + 1}{2} - 1

What is the inverse of f(x)=4(x+1)^2-1 ?
The inverse of f(x)=4(x+1)^2-1 is (sqrt(x+1))/2-1,-(sqrt(x+1))/2-1