f(x)=ln(cosh(x))

Lösung

f (x) = ln (cosh (x))

Parity : Gerade

Inverse : arccosh (e^{x})

Schritte zur Lösung

Parity of

ln (cosh (x)) :

Gerade

Umkehrung von

ln (cosh (x)) : arccosh (e^{x})

f (x) = \frac{x + 1}{3 x + 1}

y^{2} = 4 (x + 4)^{3}, 0 \leq x \leq 2

y = e^{x + 3}

f (x) = 1 - x^{2}, - 1 \leq x \leq 1

f (x) = \frac{2}{x - 7}