invers f(x)=1-cos(x)

Lösung

invers

f (x) = 1 - cos (x)

arccos (1 - x)

Schritte zur Lösung

Löse nach

cos (x), y = 1 - cos (x)

cos (x) = 1 - y

cos (a) = b \Rightarrow a = arccos (b)

arccos (1 - y)

Ersetze

y = x

arccos (1 - x)

in v erse x^{8}

in v erse f (3) = - n + 1

in v erse f (x) = 8 x + 12

in v erse f (x) = \frac{( - 3 x + 2 )}{( 4 x - 1 )}

in v erse 7 x - 1