变换 f(x)=2cos(3x+pi/2)

解答

变换

f (x) = 2 cos (3 x + \frac{π}{2})

相位 : - \frac{π}{6}, 垂直 : 0

求解步骤

f (x) = 2 cos (3 x + \frac{π}{2})

g (B x - C) = cos (3 x + \frac{π}{2}), B = 3, C = - \frac{π}{2}, D = 0

因此，相位变换

\frac{C}{B}

为

\frac{- \frac{π}{2}}{3}

- \frac{π}{6}

垂直变换

D

为

0

0