extreme f(x)=3x^2+6x+1

Lösung

extrempunkte

f (x) = 3 x^{2} + 6 x + 1

Minimum (- 1, - 2)

Schritte zur Lösung

f^{'} (x) = 6 x + 6

Intervalle finden:

Absteigend

: - \infty < x < - 1,

Ansteigend

: - 1 < x < \infty

Stecke

x = - 1

3 x^{2} + 6 x + 1 : - 2

Minimum (- 1, - 2)

e x t re m e f (x, y) = y^{3} + x^{2} - 6 x y + 3 x + 6 y - 7

e x t re m e f (x, y) = x^{2} + x y + y^{2} - 3 x - 6 y

e x t re m e f (x) = \frac{2}{3} x^{3} - x^{2} - 12 x + 3

e x t re m e f (x) = - x^{3} + 3 x^{2} + 45 x - 7

e x t re m e f (x, y) = 3 x - 2 x^{2} y + x y^{2}