3x^2+3y^2+15x-21y=110

解

3 x^{2} + 3 y^{2} + 15 x - 21 y = 110

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{331}{6}

解答ステップ

3 x^{2} + 3 y^{2} + 15 x - 21 y = 110

3 x^{2} + 3 y^{2} + 15 x - 21 y = 110

を標準的な円のequationの形式で書き換える

(x - (- \frac{5}{2}))^{2} + (y - \frac{7}{2})^{2} = (\frac{331}{6})^{2}

ゆえに円の特性は:

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{331}{6}