3x^2+y=5

Lösung

3 x^{2} + y = 5

(h, k) = (0, 5), p = - \frac{1}{12}

Schritte zur Lösung

3 x^{2} + y = 5

Rewrite

3 x^{2} + y = 5

in the standard form:

4 (- \frac{1}{12}) (y - 5) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 5), p = - \frac{1}{12}

a = \frac{2 x}{t ^{2}}

y^{(2)} - 10 y - 5 x + 15 = 0

x^{2} + y = - 1

5 x^{2} + 30 x + 24 y = 51

(x - 2)^{2} = 4 (y + 5)