a^2+b^2=100

解答

a^{2} + b^{2} = 100

(a, b) = (0, 0), r = 10

求解步骤

a^{2} + b^{2} = 100

将

a^{2} + b^{2} = 100

改写为圆标准方程

(a - 0)^{2} + (b - 0)^{2} = 1 0^{2}

因此圆的性质是:

(a, b) = (0, 0), r = 10

x^{2} + y^{2} - 6 x + 4 y = 12

x^{2} + y^{2} - 8 x - 10 y + 5 = 0

9 x^{2} - 6 x + 9 + 9 y^{2} + 24 y + 144 = 172

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1