8x+32y+y^2=-263-x^2

解答

8 x + 32 y + y^{2} = - 263 - x^{2}

(a, b) = (- 4, - 16), r = 3

求解步骤

8 x + 32 y + y^{2} = - 263 - x^{2}

将

8 x + 32 y + y^{2} = - 263 - x^{2}

改写为圆标准方程

(x - (- 4))^{2} + (y - (- 16))^{2} = 3^{2}

因此圆的性质是:

(a, b) = (- 4, - 16), r = 3

2 x^{2} + 2 y^{2} - 8 x + 28 y + 86 = 0

(x + 12)^{2} + (Y (x) - 4)^{2} - 30 = 0

x^{2} + y^{2} - x + 6 y + 9 = 0

x^{2} + y^{2} + 24 x + 10 y + 160 = 0

x^{2} + (y - 3)^{2} = 1