x^2+y^2-1/4 x+1/4 y= 7/32

解

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

(a, b) = (\frac{1}{8}, - \frac{1}{8}), r = \frac{1}{2}

解答ステップ

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

を標準的な円のequationの形式で書き換える

(x - \frac{1}{8})^{2} + (y - (- \frac{1}{8}))^{2} = (\frac{1}{2})^{2}

ゆえに円の特性は:

(a, b) = (\frac{1}{8}, - \frac{1}{8}), r = \frac{1}{2}