a^2-28+b^2=7

解答

a^{2} - 28 + b^{2} = 7

(a, b) = (0, 0), r = 35

求解步骤

a^{2} - 28 + b^{2} = 7

将

a^{2} - 28 + b^{2} = 7

改写为圆标准方程

(a - 0)^{2} + (b - 0)^{2} = (35)^{2}

因此圆的性质是:

(a, b) = (0, 0), r = 35

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x^{2} + y^{2} + 6 y - 18 = 0

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