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Beliebt Geometry >

a^2-2a+b^2-2b>= 0

Lösung

a^{2} - 2 a + b^{2} - 2 b \geq 0

Lösung

(a, b) = (1, 1), r = 2

Schritte zur Lösung

a^{2} - 2 a + b^{2} - 2 b \geq 0

Rewrite

a^{2} - 2 a + b^{2} - 2 b \geq 0

in the form of the standard circle equation

(a - 1)^{2} + (b - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

Graph

Beliebte Beispiele

(x+3)^2+(y-1)^2=121

(x + 3)^{2} + (y - 1)^{2} = 121

(x-2)^2+(y-1)^2=8

(x - 2)^{2} + (y - 1)^{2} = 8

4x^2+32x+4y^2+20y=0

4 x^{2} + 32 x + 4 y^{2} + 20 y = 0

z^{2} + 1^{2} + y^{2} = 16

(x+3)^2+(y+4)^2=4

(x + 3)^{2} + (y + 4)^{2} = 4