2x^2-8x+6y+10=0

Lösung

2 x^{2} - 8 x + 6 y + 10 = 0

(h, k) = (2, - \frac{1}{3}), p = - \frac{3}{4}

Schritte zur Lösung

2 x^{2} - 8 x + 6 y + 10 = 0

Rewrite

2 x^{2} - 8 x + 6 y + 10 = 0

in the standard form

4 (- \frac{3}{4}) (y - (- \frac{1}{3})) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - \frac{1}{3}), p = - \frac{3}{4}