(x^2-10x)+(y^2+9y)=-1

解

(x^{2} - 10 x) + (y^{2} + 9 y) = - 1

(a, b) = (5, - \frac{9}{2}), r = \frac{177}{2}

解答ステップ

x^{2} - 10 x + (y^{2} + 9 y) = - 1

x^{2} - 10 x + (y^{2} + 9 y) = - 1

を標準的な円のequationの形式で書き換える

(x - 5)^{2} + (y - (- \frac{9}{2}))^{2} = (\frac{177}{2})^{2}

ゆえに円の特性は:

(a, b) = (5, - \frac{9}{2}), r = \frac{177}{2}