9x^2+54x+9y^2-6y=-64

解答

9 x^{2} + 54 x + 9 y^{2} - 6 y = - 64

(a, b) = (- 3, \frac{1}{3}), r = 2

求解步骤

9 x^{2} + 54 x + 9 y^{2} - 6 y = - 64

将

9 x^{2} + 54 x + 9 y^{2} - 6 y = - 64

改写为圆标准方程

(x - (- 3))^{2} + (y - \frac{1}{3})^{2} = (2)^{2}

因此圆的性质是:

(a, b) = (- 3, \frac{1}{3}), r = 2

x^{2} + y^{2} - 6 x - 4 y - 8 = 0

x^{2} + y^{2} + x - 2 y = 25

(x - 11)^{2} + (y + 11)^{2} = 144

x^{2} - 8 x + y^{2} - 2 y = 19

x^{2} + y^{2} - 2 x \geq 0