2x^2-12x+14-14y=0

Lösung

2 x^{2} - 12 x + 14 - 14 y = 0

(h, k) = (3, - \frac{2}{7}), p = \frac{7}{4}

Schritte zur Lösung

2 x^{2} - 12 x + 14 - 14 y = 0

Rewrite

2 x^{2} - 12 x + 14 - 14 y = 0

in the standard form

4 \cdot \frac{7}{4} (y - (- \frac{2}{7})) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - \frac{2}{7}), p = \frac{7}{4}