de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

2x^2+2y^2-3x+5y-4=0

Lösung

2 x^{2} + 2 y^{2} - 3 x + 5 y - 4 = 0

Lösung

(a, b) = (\frac{3}{4}, - \frac{5}{4}), r = \frac{33}{2 2}

Schritte zur Lösung

2 x^{2} + 2 y^{2} - 3 x + 5 y - 4 = 0

Rewrite

2 x^{2} + 2 y^{2} - 3 x + 5 y - 4 = 0

in the form of the standard circle equation

(x - \frac{3}{4})^{2} + (y - (- \frac{5}{4}))^{2} = (\frac{33}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{4}, - \frac{5}{4}), r = \frac{33}{2 2}

Graph

Beliebte Beispiele

(x-3)^2+(y-5)^2=25

(x - 3)^{2} + (y - 5)^{2} = 25

x^2+y^2+10x-16y+64=0

x^{2} + y^{2} + 10 x - 16 y + 64 = 0

2(x^2-3)+2(y^2-1)=45

2 (x^{2} - 3) + 2 (y^{2} - 1) = 45

(x+2)^2+(y-1.5)^2=(sqrt(2.75)i)

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)

x^2+4x+y^2+10y=-20

x^{2} + 4 x + y^{2} + 10 y = - 20