4(x-1)^2+4y^2=9

解答

4 (x - 1)^{2} + 4 y^{2} = 9

(a, b) = (1, 0), r = \frac{3}{2}

求解步骤

4 (x - 1)^{2} + 4 y^{2} = 9

将

4 (x - 1)^{2} + 4 y^{2} = 9

改写为圆标准方程

(x - 1)^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

因此圆的性质是:

(a, b) = (1, 0), r = \frac{3}{2}

(x - 2)^{2} + (y + 4)^{2} = 3

x^{2} + y^{2} \geq 36

(x - 2)^{2} + (y + 9)^{2} = 196

3 x^{2} + 3 y^{2} - 30 x - 6 y + 75 = 0

0.2 x^{2} + x + 0.2 y^{2} - 4 y = 1