x^2-4x-2y+10=0

Lösung

x^{2} - 4 x - 2 y + 10 = 0

(h, k) = (2, 3), p = \frac{1}{2}

Schritte zur Lösung

x^{2} - 4 x - 2 y + 10 = 0

Rewrite

x^{2} - 4 x - 2 y + 10 = 0

in the standard form

4 \cdot \frac{1}{2} (y - 3) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 3), p = \frac{1}{2}