y^2+14y+4x+45=0

Lösung

y^{2} + 14 y + 4 x + 45 = 0

(h, k) = (1, - 7), p = - 1

Schritte zur Lösung

y^{2} + 14 y + 4 x + 45 = 0

Rewrite

y^{2} + 14 y + 4 x + 45 = 0

in the standard form

4 (- 1) (x - 1) = (y - (- 7))^{2}

Therefore parabola properties are:

(h, k) = (1, - 7), p = - 1