((2x-2)^2)/2+((2y+6)^2)/2 = 46/2

解答

\frac{( 2 x - 2 ) ^{2}}{2} + \frac{( 2 y + 6 ) ^{2}}{2} = \frac{46}{2}

(a, b) = (1, - 3), r = \frac{23}{2}

求解步骤

\frac{( 2 x - 2 ) ^{2}}{2} + \frac{( 2 y + 6 ) ^{2}}{2} = \frac{46}{2}

将

\frac{( 2 x - 2 ) ^{2}}{2} + \frac{( 2 y + 6 ) ^{2}}{2} = \frac{46}{2}

改写为圆标准方程

(x - 1)^{2} + (y - (- 3))^{2} = (\frac{23}{2})^{2}

因此圆的性质是:

(a, b) = (1, - 3), r = \frac{23}{2}

x^{2} + y^{2} - 2 x - 8 y + 1 = 0

(x - 5)^{2} + (Y (x) + 2)^{2} = 16

2 x^{2} + 12 x + 2 y^{2} - 2 y - 3 = 0

(X + 7)^{2} + (y - 1)^{2} = 9

(x + 7)^{2} + (y - 6)^{2} = 361