x= 1/2 at^2

Lösung

x = \frac{1}{2} a t^{2}

(h, k) = (0, 0), p = \frac{1}{2 a}

Schritte zur Lösung

x = \frac{1}{2} a t^{2}

Rewrite

x = \frac{1}{2} a t^{2}

in the standard form:

4 \cdot \frac{1}{2 a} (x - 0) = (t - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{2 a}