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Beliebt Geometry >

center 4x^2+4y^2-4x+2y+1=0

Lösung

center

4 x^{2} + 4 y^{2} - 4 x + 2 y + 1 = 0

Lösung

(\frac{1}{2}, - \frac{1}{4})

Schritte zur Lösung

4 x^{2} + 4 y^{2} - 4 x + 2 y + 1 = 0

Rewrite

4 x^{2} + 4 y^{2} - 4 x + 2 y + 1 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{1}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{1}{4}

And the center is:

(\frac{1}{2}, - \frac{1}{4})

Graph

Beliebte Beispiele

center x^2+y^2+14x-16y=87

ce n t er x^{2} + y^{2} + 14 x - 16 y = 87

center (x-4)^2+(y-1)^2=4

ce n t er (x - 4)^{2} + (y - 1)^{2} = 4

center 4x^2+4y^2+12x-4y-90=0

ce n t er 4 x^{2} + 4 y^{2} + 12 x - 4 y - 90 = 0

center x^2+y^2+4x-6y=12

ce n t er x^{2} + y^{2} + 4 x - 6 y = 12

center x^2=16-y^2

ce n t er x^{2} = 16 - y^{2}