中心 (x-1/2)^2+(y-1/2)^2= 9/4

解答

中心

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

(\frac{1}{2}, \frac{1}{2})

求解步骤

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

将

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

改写为圆标准方程

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{3}{2})^{2}

因此圆的性质是:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

中心是:

(\frac{1}{2}, \frac{1}{2})

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