49y^2-392x+28y+732=0

Lösung

49 y^{2} - 392 x + 28 y + 732 = 0

(h, k) = (\frac{13}{7}, - \frac{2}{7}), p = 2

Schritte zur Lösung

49 y^{2} - 392 x + 28 y + 732 = 0

Rewrite

49 y^{2} - 392 x + 28 y + 732 = 0

in the standard form

4 \cdot 2 (x - \frac{13}{7}) = (y - (- \frac{2}{7}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{13}{7}, - \frac{2}{7}), p = 2

(y - 4)^{2} = 16 x

x = y^{2} + 6

6 x^{2} + 12 x + y + 13 = 0

y + x^{2} = 6

y + x^{2} = 0