3x^2+3y=0

Lösung

3 x^{2} + 3 y = 0

(h, k) = (0, 0), p = - \frac{1}{4}

Schritte zur Lösung

3 x^{2} + 3 y = 0

Rewrite

3 x^{2} + 3 y = 0

in the standard form:

4 (- \frac{1}{4}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{4}

y^{2} - 6 x = - 14 y - 49

y^{2} = x + 25

- f (x) = 4 x^{2} + 4 x - 2

(y - (- 1))^{2} = 2 (x - 1)

y > - x^{2} - 3 x + 1