4x^2=-y

Lösung

4 x^{2} = - y

(h, k) = (0, 0), p = - \frac{1}{16}

Schritte zur Lösung

4 x^{2} = - y

Rewrite

4 x^{2} = - y

in the standard form:

4 (- \frac{1}{16}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{16}

x - y^{2} = 3

x - y^{2} = 5

12 y + x^{2} = 0

2 x^{2} - 4 x + y - 3 = 0

- f (x) = 4 x^{2} + 2 x - 2