半径 (x+6)^2+(y+5)^2=8

解答

半径

(x + 6)^{2} + (y + 5)^{2} = 8

r = 8

求解步骤

(x + 6)^{2} + (y + 5)^{2} = 8

将

(x + 6)^{2} + (y + 5)^{2} = 8

改写为圆标准方程

(x - (- 6))^{2} + (y - (- 5))^{2} = (8)^{2}

因此圆的性质是:

(a, b) = (- 6, - 5), r = 8

半径是:

r = 8

r a d i u s x^{2} + y^{2} - 4 x - 7 = 0

r a d i u s 2 x^{2} + 2 y^{2} - 17 x = 0

r a d i u s 4 x^{2} + 4 y^{2} + 40 x - 32 y = 5

r a d i u s (y + 8)^{2} + (x + 2)^{2} = 72

r a d i u s 5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0