半径 x^2+y^2-6x+10y+9=0

解答

半径

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

r = 5

求解步骤

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

将

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

改写为圆标准方程

(x - 3)^{2} + (y - (- 5))^{2} = 5^{2}

因此圆的性质是:

(a, b) = (3, - 5), r = 5

半径是:

r = 5

r a d i u s 2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

r a d i u s x^{2} - 6 x + 9 + y^{2} - 4 y + 4 = 16

r a d i u s x^{2} + y^{2} - 4 x + 6 y - 3 = 0

r a d i u s (x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

r a d i u s (x + \frac{8}{3})^{2} + y^{2} = 1