-x^2-12x+12y-96=0

Lösung

- x^{2} - 12 x + 12 y - 96 = 0

(h, k) = (- 6, 5), p = 3

Schritte zur Lösung

- x^{2} - 12 x + 12 y - 96 = 0

Rewrite

- x^{2} - 12 x + 12 y - 96 = 0

in the standard form

4 \cdot 3 (y - 5) = (x - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 6, 5), p = 3

y - x^{2} > 0

y - 2 = (x - 1)^{2}

y - 2 = x^{2} - x - 1

x^{2} - 4 y = 1

2 x^{2} - 13 x + k (x) = 0