de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

4x^2+16y^2-4x-32y+1=0

Lösung

4 x^{2} + 16 y^{2} - 4 x - 32 y + 1 = 0

Lösung

(h, k) = (\frac{1}{2}, 1), a = 2, b = 1

Schritte zur Lösung

4 x^{2} + 16 y^{2} - 4 x - 32 y + 1 = 0

Rewrite

4 x^{2} + 16 y^{2} - 4 x - 32 y + 1 = 0

in the form of the standard ellipse equation

\frac{( x - \frac{1}{2} ) ^{2}}{2 ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (\frac{1}{2}, 1), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (\frac{1}{2}, 1), a = 2, b = 1

Graph

Beliebte Beispiele

x = (y + 2)^{2}

exzentrizität x^2-y^2=4

ecce n t r i c i t y x^{2} - y^{2} = 4

scheitelpunkte f(x)=x^2+5x+6

v er t i ces f (x) = x^{2} + 5 x + 6

2x^2+2y^2-2x-2y-3=0

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

foki (x^2)/(36)+(y^2)/(25)=1

f oc i \frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1