3y^2-4x-6y+8=0

Lösung

3 y^{2} - 4 x - 6 y + 8 = 0

(h, k) = (\frac{5}{4}, 1), p = \frac{1}{3}

Schritte zur Lösung

3 y^{2} - 4 x - 6 y + 8 = 0

Rewrite

3 y^{2} - 4 x - 6 y + 8 = 0

in the standard form

4 \cdot \frac{1}{3} (x - \frac{5}{4}) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{4}, 1), p = \frac{1}{3}

(x - 1)^{2} = 4 y

x - y^{2} > 1

(x + 5)^{2} = - 18 (y - 3)

x^{2} = 4 y + 4

x^{2} + 4 x + 4 y = 4