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Beliebt Geometry >

((x-2)^2)/(10)+((y+1)^2)/(25)=1

Lösung

\frac{( x - 2 ) ^{2}}{10} + \frac{( y + 1 ) ^{2}}{25} = 1

Lösung

(h, k) = (2, - 1), a = 10, b = 5

Schritte zur Lösung

\frac{( x - 2 ) ^{2}}{10} + \frac{( y + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{10} + \frac{( y + 1 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{( 10 ) ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 10, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), b = 5, a = 10

Graph

Beliebte Beispiele

36x^2+16y^2+144x-160y-32=0

36 x^{2} + 16 y^{2} + 144 x - 160 y - 32 = 0

9x^2+49y^2-114x+490y+1360=0

9 x^{2} + 49 y^{2} - 114 x + 490 y + 1360 = 0

((x-2)^2}{25}+\frac{(v+3)^2)/9 =1

\frac{( x - 2 ) ^{2}}{25} + \frac{( v + 3 ) ^{2}}{9} = 1

((x+2)^2)/9+((y-1)^2)/4 =1

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

16(x^2)+9(y^2)-144=0

16 (x^{2}) + 9 (y^{2}) - 144 = 0