((x-5)^2}{2^2}+\frac{(y-3)^2)/9 =1

Lösung

\frac{( x - 5 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{9} = 1

(h, k) = (5, 3), a = 2, b = 3

Schritte zur Lösung

\frac{( x - 5 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, 3), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (5, 3), b = 3, a = 2

25 x^{2} + 9 y^{2} + 100 x - 125 = 0

\frac{1}{x + i y} + \frac{1}{x - i y} < - 1

6 x^{2} + 9 y^{2} - 24 x - 54 y + 51 = 0

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{25} = 1

1 x^{2} + 3 y^{2} + 9 x + 8 y - 14 = 0